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vanishing points of a homogeneous ideal https://www.singular.uni-kl.de/forum/viewtopic.php?f=10&t=2565 |
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Author: | ibahmani [ Wed Jan 11, 2017 7:28 pm ] |
Post subject: | vanishing points of a homogeneous ideal |
I am trying to find vanishing points of a homogeneous ideal I tried to use Singular to find but it seems there is not any function. Is there anyone who knows to do it? Has anyone tried it? I=(wxy + x^2y + xy^2 + xyz, w^2y + wxy + wy^2 + wyz, w^2x + wx^2 + wxy + wxz, wxy) |
Author: | steenpass [ Thu Jan 12, 2017 9:25 am ] |
Post subject: | Re: vanishing points of a homogeneous ideal |
The zero set of this ideal is two-dimensional: Code: > ring r = 0, (w,x,y,z), dp; > ideal I = wxy + x2y + xy2 + xyz, w2y + wxy + wy2 + wyz, w2x + wx2 + wxy + wxz, wxy; > I = std(I); > I; I[1]=x2y+xy2+xyz I[2]=wxy I[3]=w2y+wy2+wyz I[4]=w2x+wx2+wxz > dim(I); 2 Given the above standard basis, it's relatively easy to compute the vanishing set 'by hand'. If not, then computing a primary decomposition might help: Code: > LIB "primdec.lib";
[snip] > primdecGTZ(I); [1]: [1]: _[1]=x _[2]=w+y+z [2]: _[1]=x _[2]=w+y+z [2]: [1]: _[1]=y _[2]=w+x+z [2]: _[1]=y _[2]=w+x+z [3]: [1]: _[1]=y _[2]=x [2]: _[1]=y _[2]=x [4]: [1]: _[1]=x+y+z _[2]=w [2]: _[1]=x+y+z _[2]=w [5]: [1]: _[1]=y _[2]=w [2]: _[1]=y _[2]=w [6]: [1]: _[1]=x _[2]=w [2]: _[1]=x _[2]=w |
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